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5x^2+42x-80=0
a = 5; b = 42; c = -80;
Δ = b2-4ac
Δ = 422-4·5·(-80)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-58}{2*5}=\frac{-100}{10} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+58}{2*5}=\frac{16}{10} =1+3/5 $
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